×

# BUCKYBALL. .....THAT'S FULLERENCE

U all know the No. Of five member rings & six member rings in fullerence that is 12 & 20 respectively. But have u ever tried to find that how it came. ...

...Answer -observe the structure of fullerence. Each C atom contributs it ' 2/3 part in two six member rings. & remaining 1 / 3part is in the five member ring so each 6 member ring is made up of net 2 C atoms & five member ring is made up of net 5 / 3 C atoms. Out of 60 C atoms net 40 atoms forms six member rings.& remaining 20 atoms form five member rings. ...so

NO. Of 6 member rings = 40 / 2 = 20 & NO. Of five member rings = 20 divided by 5 / 3 = 12. ..

Note by Kiran Chillewad
3 years, 8 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

## Comments

Sort by:

Top Newest

What about the Boron Fullerene? B40 if I am not mistaken...

- 2 years, 7 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...