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f(x)=(x-α)(x-β).... prove derivative of f(x)/f(x) = 1/x-α+1/x-β....

Note by Hrushikesh Behera 1 year, 2 months ago

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\(f(x)=(x-\alpha)(x-\beta)\)

\(\log(|f(x)|)=\log(|x-\alpha|)+\log(|x-\beta|)\)

\(\text{Differentiating,we get,}\)

\(\dfrac{f'(x)}{f(x)}=\dfrac{1}{(x-\alpha)}+\dfrac{1}{(x-\beta)}\)

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`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

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Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

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TopNewest\(f(x)=(x-\alpha)(x-\beta)\)

\(\log(|f(x)|)=\log(|x-\alpha|)+\log(|x-\beta|)\)

\(\text{Differentiating,we get,}\)

\(\dfrac{f'(x)}{f(x)}=\dfrac{1}{(x-\alpha)}+\dfrac{1}{(x-\beta)}\)

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