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# Can anyone help me

$$P,Q,R,S$$ are the centres of the four circles each of which is cut by a fixed circle orthogonally. If $$I^{2}_1,I^{2}_2,I^{2}_3,I^{2}_4$$ are the squares of length of tangents to the four circles from a point in their plane then

$$a.$$ $$I^{2}_1\Delta QRS-I^{2}_2\Delta RSP+I^{2}_3\Delta SPQ-I^{2}_4\Delta PQR=0$$

$$b.$$ $$I^{2}_1\Delta QRS+I^{2}_2\Delta RSP-I^{2}_3\Delta SPQ+I^{2}_4\Delta PQR=0$$

$$c.$$ $$I^{2}_1\Delta QRS-I^{2}_2\Delta RSP+I^{2}_3\Delta SPQ-I^{2}_4\Delta PQR=-1$$

$$d.$$ none of these

Note by Anish Raj
1 year, 5 months ago

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Could you explain the notation that you have used in the first three options? · 1 year, 5 months ago

Those are notation of “triange”. · 1 year, 5 months ago

Even I know that.What I want to ask is what do we mean by $$I1^2$$triangle QRS.Does it mean square of tangent length from a fixed point to circumcircle of triangle QRS. · 1 year, 5 months ago

Comment deleted Apr 09, 2016

How can anyone draw a tangent to area of triangle?What do you mean by this absurd statement? · 1 year, 5 months ago

Hey I am not very good in geometry that's why I am asking for help · 1 year, 5 months ago