\(P,Q,R,S\) are the centres of the four circles each of which is cut by a fixed circle orthogonally. If \(I^{2}_1,I^{2}_2,I^{2}_3,I^{2}_4\) are the squares of length of tangents to the four circles from a point in their plane then

\(a.\) \(I^{2}_1\Delta QRS-I^{2}_2\Delta RSP+I^{2}_3\Delta SPQ-I^{2}_4\Delta PQR=0\)

\(b.\) \(I^{2}_1\Delta QRS+I^{2}_2\Delta RSP-I^{2}_3\Delta SPQ+I^{2}_4\Delta PQR=0\)

\(c.\) \(I^{2}_1\Delta QRS-I^{2}_2\Delta RSP+I^{2}_3\Delta SPQ-I^{2}_4\Delta PQR=-1\)

\(d.\) none of these

## Comments

Sort by:

TopNewestCould you explain the notation that you have used in the first three options? – Indraneel Mukhopadhyaya · 1 year, 1 month ago

Log in to reply

– Anish Raj · 1 year, 1 month ago

Those are notation of “triange”.Log in to reply

– Indraneel Mukhopadhyaya · 1 year, 1 month ago

Even I know that.What I want to ask is what do we mean by \(I1^2\)triangle QRS.Does it mean square of tangent length from a fixed point to circumcircle of triangle QRS.Log in to reply

Log in to reply

– Indraneel Mukhopadhyaya · 1 year, 1 month ago

How can anyone draw a tangent to area of triangle?What do you mean by this absurd statement?Log in to reply

– Anish Raj · 1 year, 1 month ago

Hey I am not very good in geometry that's why I am asking for helpLog in to reply

@Nihar mahajan , @cheo-sheong cheong help – Anish Raj · 1 year, 1 month ago

Log in to reply