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# Can someone tell me how to approach and solve this problem..?

If $(1+ax)^{n}=1+8x+24x^2+...$ and a line through P(a , n) cuts the circle $x^2+y^2=4$ in A and B then PA.PB is equal to $(a)4$ $(b)8$ $(c)16$ $(d)32$

Please explain the solution in DETAIL .....

Note by Parag Zode
2 years ago

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$$(1+ax)^{n}=1+n*ax+\dfrac{n(n-1)}{2}*a^{2}*x^{2}+.........=1+8x+24x^{2}+.......Comparing\ \\co-efficients,we\ get a*n=8\ and\ (n-1)*(a)=6.Solving\ these\ two\ we\ get:a=2\ and\ n=4.So\ the\ \\point\ P\ is(2,4).Now,length\ of\ the\ tangent\ on\ the\ given\ circle\ is\\=\sqrt{2^{2}+4^{2}-4}.This\ comes\ to\ 4.Now,PA*PB=PT^{2}=4^{2}.\\Therefore,PA*PB=16.PT:length\ of\ the\ tangent\ to\ the\ circle\ from\ P.$$ · 2 years ago