If \[(1+ax)^{n}=1+8x+24x^2+...\] and a line through P(a , n) cuts the circle \[x^2+y^2=4\] in A and B then PA.PB is equal to \[(a)4\] \[(b)8\] \[(c)16\] \[(d)32\]

Please explain the solution in DETAIL .....

If \[(1+ax)^{n}=1+8x+24x^2+...\] and a line through P(a , n) cuts the circle \[x^2+y^2=4\] in A and B then PA.PB is equal to \[(a)4\] \[(b)8\] \[(c)16\] \[(d)32\]

Please explain the solution in DETAIL .....

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewest\((1+ax)^{n}=1+n*ax+\dfrac{n(n-1)}{2}*a^{2}*x^{2}+.........=1+8x+24x^{2}+.......Comparing\ \\co-efficients,we\ get a*n=8\ and\ (n-1)*(a)=6.Solving\ these\ two\ we\ get:a=2\ and\ n=4.So\ the\ \\point\ P\ is(2,4).Now,length\ of\ the\ tangent\ on\ the\ given\ circle\ is\\=\sqrt{2^{2}+4^{2}-4}.This\ comes\ to\ 4.Now,PA*PB=PT^{2}=4^{2}.\\Therefore,PA*PB=16.PT:length\ of\ the\ tangent\ to\ the\ circle\ from\ P.\) – Satyendra Kumar · 2 years, 9 months ago

Log in to reply

this for more info! – Pranjal Jain · 2 years, 8 months ago

Nice solution! I advise you not to use latex in typing text! It will look more pleasant! SeeLog in to reply