Find the value of B for any real numbers A and B such that

A + B = $$A^{2}$$ - $$B^{2}$$ = AB0 .a

Note by Kenneth Gravamen
3 years ago

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$\alpha+\beta = \alpha^{2}-\beta^{2}\ = (\alpha+\beta)(\alpha-\beta)$ Here, if $$\alpha+\beta = 0$$, the equation will be true, therefore one of the answer is $$\beta = -\alpha$$, but if $$\alpha+\beta \neq 0$$, you will get $$1 = \alpha-\beta$$ or $$\beta = \alpha-1$$. $$\beta$$ may be represented as $$\beta = -\alpha, \alpha-1$$

- 3 years ago