# Can you help me with this? Permutation ....

In how many ways can 6 mathematics and 3 design books is arranged on a half if design books are not to be separated?

Note by Crischell Baylon
4 years, 1 month ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

See, Let there be a case in which the three design books are on one side of the shelf covering three out of nine places. Now, the ways to arrange those three design books is 3! = 6 and the number of ways to arrange the rest of the mathematics books is 6!. So total ways are 6! x 3! = 4320. But the set of three design books can be moved to different 3 places instead of the first three. So total ways are 7 x 4320= 30240.

- 4 years, 1 month ago