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\(L.H.S=l(\sin(\theta)\cos(\phi)+\sin(\phi)\cos(\theta))=l \left(\dfrac{BC \cdot n}{l^2}+\dfrac{m \cdot DC}{l^2}\right)=\dfrac 1 l \left(BC \cdot n+DC \cdot m \right)\).

\(R.H.S= n \cdot \dfrac{BC}{l}+m \cdot \dfrac{CD}{l}=\dfrac 1 l \left(BC \cdot n+DC \cdot m \right)\).

\(L.H.S=R.H.S\). Proved. – Svatejas Shivakumar · 11 months, 3 weeks ago

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– Deeparaj Bhat · 11 months, 3 weeks ago

But it's not given that \(AC\) is a diameter right?Log in to reply

– Svatejas Shivakumar · 11 months, 3 weeks ago

I guess we have to assume that it is.Log in to reply