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# Circle

Note by محمد مصباح
1 year, 3 months ago

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· 10 months, 3 weeks ago

$$L.H.S=l(\sin(\theta)\cos(\phi)+\sin(\phi)\cos(\theta))=l \left(\dfrac{BC \cdot n}{l^2}+\dfrac{m \cdot DC}{l^2}\right)=\dfrac 1 l \left(BC \cdot n+DC \cdot m \right)$$.

$$R.H.S= n \cdot \dfrac{BC}{l}+m \cdot \dfrac{CD}{l}=\dfrac 1 l \left(BC \cdot n+DC \cdot m \right)$$.

$$L.H.S=R.H.S$$. Proved. · 1 year, 3 months ago

But it's not given that $$AC$$ is a diameter right? · 1 year, 3 months ago

I guess we have to assume that it is. · 1 year, 3 months ago

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