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C1 : x2 y2 - 2ax + c = 0 lies completely inside C2 : x2 y2 - 2bx + c = 0 ; (a not equals b), then prove that ab>c>0

Note by Gopal Chpidhary
4 years, 1 month ago

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I would like to clarify but the equations stated doesn't look like the equations for a circle.

John Ashley Capellan - 4 years, 1 month ago

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that's x^2 + y^2 -2ax +c = 0 and x^2 + y^2-2bx+c=0..........try with this

Gopal Chpidhary - 4 years, 1 month ago

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Also, ab > c > 0 is to be proven?

John Ashley Capellan - 4 years, 1 month ago

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