Waste less time on Facebook — follow Brilliant.
×

circles

C1 : x2 y2 - 2ax + c = 0 lies completely inside C2 : x2 y2 - 2bx + c = 0 ; (a not equals b), then prove that ab>c>0

Note by Gopal Chpidhary
3 years, 8 months ago

No vote yet
1 vote

Comments

Sort by:

Top Newest

I would like to clarify but the equations stated doesn't look like the equations for a circle. John Ashley Capellan · 3 years, 8 months ago

Log in to reply

@John Ashley Capellan that's x^2 + y^2 -2ax +c = 0 and x^2 + y^2-2bx+c=0..........try with this Gopal Chpidhary · 3 years, 8 months ago

Log in to reply

@Gopal Chpidhary Also, ab > c > 0 is to be proven? John Ashley Capellan · 3 years, 8 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...