# circles

C1 : x2 y2 - 2ax + c = 0 lies completely inside C2 : x2 y2 - 2bx + c = 0 ; (a not equals b), then prove that ab>c>0

Note by Gopal Chpidhary
4 years, 9 months ago

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I would like to clarify but the equations stated doesn't look like the equations for a circle.

- 4 years, 9 months ago

that's x^2 + y^2 -2ax +c = 0 and x^2 + y^2-2bx+c=0..........try with this

- 4 years, 9 months ago

Also, ab > c > 0 is to be proven?

- 4 years, 9 months ago