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C1 : x2 y2 - 2ax + c = 0 lies completely inside C2 : x2 y2 - 2bx + c = 0 ; (a not equals b), then prove that ab>c>0

Note by Gopal Chpidhary 3 years, 8 months ago

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I would like to clarify but the equations stated doesn't look like the equations for a circle. – John Ashley Capellan · 3 years, 8 months ago

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@John Ashley Capellan – that's x^2 + y^2 -2ax +c = 0 and x^2 + y^2-2bx+c=0..........try with this – Gopal Chpidhary · 3 years, 8 months ago

@Gopal Chpidhary – Also, ab > c > 0 is to be proven? – John Ashley Capellan · 3 years, 8 months ago

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TopNewestI would like to clarify but the equations stated doesn't look like the equations for a circle. – John Ashley Capellan · 3 years, 8 months ago

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– Gopal Chpidhary · 3 years, 8 months ago

that's x^2 + y^2 -2ax +c = 0 and x^2 + y^2-2bx+c=0..........try with thisLog in to reply

– John Ashley Capellan · 3 years, 8 months ago

Also, ab > c > 0 is to be proven?Log in to reply