how do you conclude that 7+7=5,it's turning out to be clueless,but you say B+D=E may be true for if you assume the order of these alphabets in increasing order or assinging the number 1,3,4 to each of them respectively.....again you say 1+1=2...this also evokes question for its utility in the representation of the alphabets ....what does it denote....???

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TopNewesthow do you conclude that 7+7=5,it's turning out to be clueless,but you say B+D=E may be true for if you assume the order of these alphabets in increasing order or assinging the number 1,3,4 to each of them respectively.....again you say 1+1=2...this also evokes question for its utility in the representation of the alphabets ....what does it denote....???

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7 + 7 = 14, 1 + 4 = 5

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oh...!!..good job....

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In short, \( 7+7 \equiv 5 (mod 9) \)

In fact if you try

0, 1, 2, 3, 4, 5....k

k, (k-1)...., 3, 2, 1, 0

a+b=c implies (k-a)+(k-b)=k+(k-a-b)

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