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Complex exponent

Can anyone tell me the value of i^i

Note by Naman Kapoor
2 years, 7 months ago

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i can be written as \({ e }^{ (i\frac { \pi }{ 2 } ) }\) so this expression can be written as \( { e }^{ (i\frac { \pi }{ 2 } )i }\)

Now \({ i }^{ 2 }\) =-1 so it is equal to \({ e }^{ \frac { -\pi }{ 2 } }\). Gautam Sharma · 2 years, 7 months ago

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@Gautam Sharma Thnxx buddy Naman Kapoor · 2 years, 6 months ago

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e to the power(-pi/2) Pranshul Srivastav · 2 years, 7 months ago

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