For beginners (like me) in complex here are few interesting formulae

$$i=\sqrt { -1 }$$

$${ i }^{ 4n+2 }\quad =\quad -1$$

$${ i }^{ 4n }\quad =\quad 1$$

$${ i }^{ 4n-1 }\quad =\quad -i$$

$${ i }^{ 4n+1 }\quad =\quad i$$

Here $$n\quad belongs\quad to\quad integers$$

You can use this to calculate i raised to any power

PS: Try proving them

Note by Parth Deshpande
2 years, 7 months ago

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