The Continuum Hypothesis claims that

There is no set whose cardinality is strictly between that of integers and real numbers.

I went out on an adventure checking what people think about it.

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## Comments

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TopNewestHave u really chatted with them? @Agnishom Chattopadhyay

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Yes. Please don't let them know it was me

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Why u did that??any purpose in mind??

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Dude, this made my day, I read this when just woke up and I believe that this was the first time I didn't sleep through a morning chem lecture.

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Glad that you like it

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WOW!!! Troll of the millennium, I wish I were there in place of those ppl you trrolled, wanna find how it feels to be trolled, @Agnishom Chattopadhyay

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Thank you for helping me with the code, Agnishom :)

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Mention not

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@John Muradeli : What do you think about this?

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LOOL AGNISHOM THIS @$*! IS HILLARIOUS!! I just read the whole thing - and I thought I was the only one going crazy in customer support chatrooms xDD

lolz I have no idea as far as the answer to that question goes, but great job trolling those cyborg representatives! cyborg cause if you look how similar their responses are, you'll see they mostly follow a script - or, a program ;)

Now if I knew what the heck a cardinal is, I might have a better idea. But I'll tell you one thing:

If a solution to that problem exists, I don't have an answer. If a solution to that problem doesn't exist, I have the answer.

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Well, this problem is called Continuum Hypothesis. You may look it up on wikipedia.

Cardinality of a set is loosely defined as the number of elements in that set. E.g, Cardinality({Calvin, Sue, Pete, Arron})=4

The cardinality of the set of real numbers is higher than the set of natural numbers, as you might notice, even though they are both infinite.

The question is if there is any set whose cardinality is between these two.

Well, if you have any chatroom transcripts, please share them.

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The complex integer set? Integers with complex interger combos.

The whole number set? Includes zero.

The rational number set? Real minus irrational.

The irrational number set? Real minus rational.

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We say that two sets are of the same cardinality if there is a bijection, i.e, an way to associate all elements of one set with all elements of the other.

For example, {Red, Green Blue} and {A,B,C} are of the same cardinality because we may establish a bijection like this:

A -> Green, B -> Blue, C -> Red

That is why we can say that the number of elements in set 1 = number of elements in set 2 or their cardinalities are equal.

It can be shown that there are as many integers as rational numbers or natural numbers by establishing a bijection between them.

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I've seen on YouTube though how the number of real numbers between 0 and 1 is greater than the number of Natural numbers due to some weird property that lets you invent more numbers than natural ones allow or some weird stuff like that...

But alright what about, at least, complex integer set? It's like complex natural numbers and their negative counterparts (and zero!). Can you "show" that too?

Anyway, I hold the answer to your question, like I said. If a condition applies...

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Post 7 in this thread

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Sorry :p

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Check that link

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Hm. Looks interesting. I'll add it to my

Importantlist for the next week (got hw from 7AP classes as of now).Thanks!

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Hahaha... LOL

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Comment deleted Oct 26, 2014

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reference

Mandatory xkcdLog in to reply

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@Agnishom Chattopadhyay , it appears that you've made a typo in the statement of the continuum hypothesis.

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Yup, fixed it. Thanks :)

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