The reason behind creating this discussion note , is to keep main contest note clean, the main contest note is getting overcrowded with discussion comments.

Feel free to discuss about problems here.

Here is a link of the contest note.

The reason behind creating this discussion note , is to keep main contest note clean, the main contest note is getting overcrowded with discussion comments.

Feel free to discuss about problems here.

Here is a link of the contest note.

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TopNewestCan someone post a formal, rigorous solution to Q5? – Sharky Kesa · 8 months, 2 weeks ago

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– Chinmay Sangawadekar · 8 months, 2 weeks ago

Well , I am also not getting that one :(Log in to reply

@Sharky Kesa Your problem is awesome

I have reached a point from which I am not able to proceed....but I am not going to give up....

Please discuss about problems here...Please avoid discussion there Thank you :) – Chinmay Sangawadekar · 8 months, 2 weeks ago

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Everybody please note that , this season is soon going to end...after @Svatejas Shivakumar' s Extra Parti.Prob. set 3 gets solved....Next season will be more interesting ! Brilliant Advanced NT Contest. All the previous contestants take this note.....

@Sharky Kesa , @Shivam Jadhav , @Harsh Shrivastava , @Alex , @Ankit Kumar Jain – Chinmay Sangawadekar · 8 months, 1 week ago

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– Alex Spagnoletti · 8 months, 1 week ago

Thank you for the contest. It has been a fantastic opportuinity to improve our Number Theory knowledge.Log in to reply

– Svatejas Shivakumar · 8 months, 1 week ago

So soon? Anyways thank you everyone for making this contest a grand success. Had great fun.Log in to reply

– Chinmay Sangawadekar · 8 months, 1 week ago

Thanks for contributing...:) second season will be more interesting and good hope you will enjoy it. Alex and Svatejas...Log in to reply

– Svatejas Shivakumar · 8 months ago

Sure it will be. When will season 2 start?Log in to reply

– Alex Spagnoletti · 8 months ago

Surely it will be so.Log in to reply

What does Spagnoletti mean when writing "there are only 2 solutions which are s + r = p"? What is s and what is r and what is the equation we are supposed to be solving? (Since the first is assumed correct for all x if I am reading it right) – Alex Li · 8 months, 1 week ago

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– Alex Li · 8 months, 1 week ago

Apparently I am just dumb, because I don't understand the next one either - a^x+b^x=2^y 1^1+3^1=2^2 a≠bLog in to reply

@Sharky Kesa please reply and change the problem title to EPP set 3 #1 – Svatejas Shivakumar · 8 months, 1 week ago

Yes probably it is positive integers other than 1.Log in to reply

– Svatejas Shivakumar · 8 months, 1 week ago

I will ask this question to him in the main note itself as I am not able to tag him.Log in to reply

This is the hardest branch of maths I think – Aakash Khandelwal · 8 months, 2 weeks ago

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Solution posted by lakshya sinha is wrong as well as the answer . I am posting the next question (6) and the answer of this question (5) – Shivam Jadhav · 8 months, 2 weeks ago

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– Chinmay Sangawadekar · 8 months, 2 weeks ago

sure ...Log in to reply

Guys I will be inactive on Brilliant for 6-7 days as I am going on holiday trip....:( :( :( :( – Chinmay Sangawadekar · 8 months, 2 weeks ago

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After shivam jadhav's problem is solved , I think we must move on to new fresh , note ....

Till Shivam's problem unsolved you can post extra participation problems ......... anybody who wants to ....but only 1 EPP is allowed . per regular question.

Keep this in Mind !!!! – Chinmay Sangawadekar · 8 months, 2 weeks ago

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– Svatejas Shivakumar · 8 months, 1 week ago

I think that you can start note-2 soon. There are well over 100 comments and it is very hard to see to where someone commented.Log in to reply

I think that it will be better if every person is allowed to post 1 EPP per regular question. – Svatejas Shivakumar · 8 months, 2 weeks ago

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– Chinmay Sangawadekar · 8 months, 2 weeks ago

okay !Log in to reply

@Svatejas Shivakumar , @Sharky Kesa

I still think that there can be some conclusion for EPP problem 1 . We are getting a number which is divisible by 2000 which has one factor which is given number , ...So there can be some relation ... – Chinmay Sangawadekar · 8 months, 2 weeks ago

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@Sharky Kesa – Chinmay Sangawadekar · 8 months, 2 weeks ago

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– Sharky Kesa · 8 months, 2 weeks ago

With the question, what you actually want to try to prove is that the expression is divisible by 16 and 125.Log in to reply