Excel in math, science, and engineering

New user? Sign up

Existing user? Sign in

Prove that the Earth's Gravity is \( \approx 9.8 \ m/s^2\)

Note by Paulo Carlos 1 year, 9 months ago

Sort by:

from Newton's law,

F=ma

GMm/R^2=ma where, 'G' is the universal gravitational constant, 'M' is the mass of the earth, 'R' is the radius of the Earth, 'm' is the mass of the body on which the force is acting and 'a' is the acc. due to gravity(g).

g=GM/R^2 =9.8 m/s^2 – Vikram Athreya · 1 year, 9 months ago

Log in to reply

g = GM/r^2 – Karan Siwach · 1 year, 9 months ago

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewestfrom Newton's law,

F=ma

GMm/R^2=ma where, 'G' is the universal gravitational constant, 'M' is the mass of the earth, 'R' is the radius of the Earth, 'm' is the mass of the body on which the force is acting and 'a' is the acc. due to gravity(g).

g=GM/R^2 =9.8 m/s^2 – Vikram Athreya · 1 year, 9 months ago

Log in to reply

g = GM/r^2 – Karan Siwach · 1 year, 9 months ago

Log in to reply