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Prove that the Earth's Gravity is \( \approx 9.8 \ m/s^2\)

Note by Paulo Carlos 2 years, 5 months ago

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from Newton's law,

F=ma

GMm/R^2=ma where, 'G' is the universal gravitational constant, 'M' is the mass of the earth, 'R' is the radius of the Earth, 'm' is the mass of the body on which the force is acting and 'a' is the acc. due to gravity(g).

g=GM/R^2 =9.8 m/s^2 – Vikram Athreya · 2 years, 5 months ago

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g = GM/r^2 – Karan Siwach · 2 years, 5 months ago

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TopNewestfrom Newton's law,

F=ma

GMm/R^2=ma where, 'G' is the universal gravitational constant, 'M' is the mass of the earth, 'R' is the radius of the Earth, 'm' is the mass of the body on which the force is acting and 'a' is the acc. due to gravity(g).

g=GM/R^2 =9.8 m/s^2 – Vikram Athreya · 2 years, 5 months ago

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g = GM/r^2 – Karan Siwach · 2 years, 5 months ago

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