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Prove that the Earth's Gravity is \( \approx 9.8 \ m/s^2\)

Note by Paulo Carlos 3 years, 9 months ago

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from Newton's law,

F=ma

GMm/R^2=ma where, 'G' is the universal gravitational constant, 'M' is the mass of the earth, 'R' is the radius of the Earth, 'm' is the mass of the body on which the force is acting and 'a' is the acc. due to gravity(g).

g=GM/R^2 =9.8 m/s^2

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g = GM/r^2

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`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

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Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

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TopNewestfrom Newton's law,

F=ma

GMm/R^2=ma where, 'G' is the universal gravitational constant, 'M' is the mass of the earth, 'R' is the radius of the Earth, 'm' is the mass of the body on which the force is acting and 'a' is the acc. due to gravity(g).

g=GM/R^2 =9.8 m/s^2

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g = GM/r^2

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