Hey guys, I saw a faster way to find cube roots.

We already know some basic cube numbers

\(0^{3}\)=0

\(1^{3}\)=1

\(2^{3}\)=8

\(3^{3}\)=27

\(4^{3}\)=64

\(5^{3}\)=125

\(6^{3}\)=216

\(7^{3}\)=343

\(8^{3}\)=512

\(9^{3}\)=729

Now, the common thing here is that each ones digit of the cube numbers is the same number that is getting cubed , except for 2 ,8 ,3 ,7 .

now let us take a cube no like 226981 .

to see which is the cube root of that number , first check the last 3 digits that is 981 . Its last digit is 1 so therefore the last digit of the cube root of 226981 is 1 .

Now for the remaining digits that is 226

Now 226 is the nearer & bigger number compared to the cube of 6 (216)

So the cube root of 226981 is 61

Let us take another example - 148877

Here 7 is in the last digit but the cube of seven's last digit is not seven. But the cube of three has the last digit as 7.

So the last digit of the cube root of 148877 is 3.

Now for the remaining digits 148.

It is the nearer and bigger than the cube of 5 (125).

Therefore the cube root of 148877 is 53.

Let us take another example 54872.

Here the last three digit's (872) last digit is 2 but the cube of 2's last digit is not 2 but the last of the cube of 8 is 2.

So the last digit of the cube root of 54872 is 8.

Now of the remaining numbers (54). It is nearer and bigger to the cube of 3 (27). So therefore the cube root of 54872 is 38.

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## Comments

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TopNewestHow about to find cube roots of a number which answer is three-digit number ?? For example 111^3, 267^3, etc

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After doing the last three digits , try to find which is the nearest cube number to it for the remaining digits E.g -

\(\sqrt[3]{1860867}\)

Done with the last three digits and the last digit , & you get 3 as the last digit of \(\sqrt[3]{1860867}\)

Now find the nearest cube number of1860 & it is 12 (1728)

So therefore \(\sqrt[3]{1860867}\) = 123

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So we just do the same ways... Thank you so much..

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waitwaitwaitwaitwait..whaaaaaaaaaaat? Where did that 3 even come from? The last digit of 1860867 is 7.....

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1), 4 (4³ = 64), 5 (5³ = 125), 6 (6³ = 216), 9 (9³ = 729) and 0 (0³ =0). But, here we see, it doesn't happen for 2 (2³ =8), neither 3 (3³ = 27), nor 7 (7³ = 343) and 8 (8³ = 512). I'll always have to check this before find cube roots by this method.Log in to reply

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Thank you, a great method to solve the cube roots, so bad it doesn't work with every cubic root, it would save a lot of time in tests. Anyway, thanks!

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Another Interesting fact:: (A) cube of 2= unit digit 8 .....cube of 8=unit digit 2 (B) cube of 3=unit digit 7...... cube of 7= unit digit 3

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1, 4, 5, 6, 9 have the unit place of their cubes as the number themselves. But cubes of 2,3 and 8,7 has there unit place as their compliment of 10.

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It works for groups of threes. How adorable.

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Cub of 2, 3, 7, 8 we have its compliment of 10.

For 2: it is 10-2=8...........for 8, it is 10-8=2............................ 3, it it 10-3=7, ......for 7, it is 10-7=3

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Data handling

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But it is not apllicable everywhere..

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Comment deleted 5 months ago

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We should take the number which has highest cube less than 117 in your case but not nearest.

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I gave the first person who introduced this to me a very good comment. Features of natural numbers can occasionally been found. Important thing is never let this concept to mislead ourselves when the situation is not whole numbers. I recalled and remember ed again but not really memorized properly. Understand why could make me a better memory perhaps. Hope I can memorize from today onwards!

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But it is not useful for non perfect cubes

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Write a comment or ask a question...if m=29 and e=13, then m=m+e e=m-e m=m-e then find the new value of m and e??

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Very nice & thanks.

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Good Method ....!!! Amazing...!!

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thats just for a sure perfect cube

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Cool.......

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Really very useful trick Thanks:)

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It's really coolest method ever.but can any1 suggests me methods for square root of a decimal number.for eg:square root of 0.56

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how to work out cube root of 216216. The answer on face is 66 but that is not the cube root.

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216216 is not perfect cube ! This method is only for perfect cube

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you have to it by long division method

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good one

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do you want to know the exact long division method of finding cube roots though it tedious... :)

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sure.

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https://brilliant.org/discussions/thread/long-divison-method-of-cube-root/

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I HAVE SOME CONFUSION THAT WHEN HAM LOG SAME NO. KO LIKHEGE OR KAB NHI........AS 1ST SUM MEN.......226 KA 6 LIKHE AND 981 KA 1 SO ANS. IS 61 BUT 148877 MEN 148 KA 5 KYU LAST NO TO 8 HA SO COMPLEMENTRY IS 2 BUT HERE IS 5..

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I would prefer not to use Hindi cause it is confusing me that you have mixed up English & Hindi

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Only works for whole numbers. It's interesting however that you have found this method. How did you come across it?

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excellent method!!! upvoted young mind :)

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I like it

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Who discovered this method? It's really awesome

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i like that method

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Real nice method. I liked it.

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I like this method .

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nice

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you mean x^3 of 226981 , 226971 , 226961 , 226981 , 226881 , all is 61 only by your way. which is incorrect

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you have to know that it it works only for a perfect cube

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I'm sorry I did not understand

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By this trick cube root for last 3 digit is depends on unit place digit only? if we consider these numbers which all have 1 as unit place digit , 226981 , 226971 , 226961 , 226221 , 226881 so by the rule cube root should be 61 for all these numbers. which is actually incorrect because numbers are different.

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excellent

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Thank U Very Much.I like Ur Way To solve The Problem.

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Great! Interesting!

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Very helpful. Thank you!

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Really good method... I like it!

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ecellent method .its working

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Good solution

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Write a comment or ask a question... Super

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Thanks

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Excellent method

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Just noticed. It actually isn't applicable to numbers other than perfect cubes. For example, if you calculate the cube root of 1,216 using this method, you get 16; actual root is 10.67. They're almost 5.5 numbers apart. If you have any better ways, please post it.

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In that case we know between which two integers the actual cube root lays.

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I had answered to a similar question , & this method is only applicable for numbers which have their cube roots with no numbers after the decimal point

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Awesome and unique way to do it!! Thanks!!

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Nice note

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Would largely help me for finding Karl Pearson's coefficient. Thanks.

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Fantastic method Thanks

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Brilliant! Good to learn this from you. Thanks.

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maths is not about approximation and estimation!!!!

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can someone prove it mathematically?

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https://brilliant.org/discussions/thread/long-divison-method-of-cube-root/

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a + 10 b + 100 c + 1000 d + 10000 e + 100000 f could roughly prove it I guess.

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@Kartik Kulkarni .... really a nice one ... but i hav a doubt ... take 1331 ..... u get 11 by the method stated above .... if u take 1441 ..... 11 isnt correct ..... in that case .... u cant find whether a no. is a cube no. or not using this method.... rite???

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also 1441's cube root is somewhat 11 And many more numbers after the decimal points

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Well actually,this method is only applicable for actual cube numbers

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Great buddy. Here is the actual method https://brilliant.org/discussions/thread/long-divison-method-of-cube-root/

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@Kartik Kulkarni ... as soon as i saw ..... i found this interesting and also concluded this is applicable for perfect cubes ... but ur inference of 1441's cube root is around 11 is wrong ..... eg: take 1721 ..... if u infer by the same method as u did above ... it is around 11 ... but actually it can be estimated to 12 ..... (Note: cube root of 1721 = 11.98)

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cool

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Really cool way...I m looking forward to u to post some cool ways of finding the sum of series....

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I love this mathed

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3√79510

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according to this cube root of 125486 should be 56 but actually it is not

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I just found out when this method works,

for eg 125486. last 3 digits = 6, first 3 digist =5,

here 125 is perfect cube , hence it doesnt work.

MY findings = This method only works when neither of the components( 1st 3 digits & last 3 digits) are perfect cube but the number that is comprised of the components is a perfect cube.

In ur case 125486 aint a perfect cube cum 125 which i call a component is.

Hows my Theorem? Thumbs up!!

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OK. what about 125000?

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125000, fr last 3 digits =0, fr first 3 digits =5

cube root of 125000 is 50.

(Notice that 000 is nothing but 0 and not 1000, 0^3 is 0)

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Comment deleted Apr 05, 2015

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Comment deleted Apr 08, 2015

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125486 is not a perfect cube and so this method is not applicable for that number

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knew that already

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Very nice and interesting solution

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whats's wrong with these four numbers(2,3,7 and 8)? i mean these are the number which you will never find at the end of any "squared number"( at ones place i mean). and here too the same four number have different digits at ones place. by the way nice trick. thanks!

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what if we have 7 digited number could u explane me how to do it please

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I just explained it to Jonathan Christianto above

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kk:":":":":":":thanku

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then we have to go by long divison actual method

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