Hey guys, I saw a faster way to find cube roots.

We already know some basic cube numbers

$0^{3}$=0

$1^{3}$=1

$2^{3}$=8

$3^{3}$=27

$4^{3}$=64

$5^{3}$=125

$6^{3}$=216

$7^{3}$=343

$8^{3}$=512

$9^{3}$=729

Now, the common thing here is that each ones digit of the cube numbers is the same number that is getting cubed , except for 2 ,8 ,3 ,7 .

now let us take a cube no like 226981 .

to see which is the cube root of that number , first check the last 3 digits that is 981 . Its last digit is 1 so therefore the last digit of the cube root of 226981 is 1 .

Now for the remaining digits that is 226

Now 226 is the nearer & bigger number compared to the cube of 6 (216)

So the cube root of 226981 is 61

Let us take another example - 148877

Here 7 is in the last digit but the cube of seven's last digit is not seven. But the cube of three has the last digit as 7.

So the last digit of the cube root of 148877 is 3.

Now for the remaining digits 148.

It is the nearer and bigger than the cube of 5 (125).

Therefore the cube root of 148877 is 53.

Let us take another example 54872.

Here the last three digit's (872) last digit is 2 but the cube of 2's last digit is not 2 but the last of the cube of 8 is 2.

So the last digit of the cube root of 54872 is 8.

Now of the remaining numbers (54). It is nearer and bigger to the cube of 3 (27). So therefore the cube root of 54872 is 38.

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## Comments

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TopNewestHow about to find cube roots of a number which answer is three-digit number ?? For example 111^3, 267^3, etc

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After doing the last three digits , try to find which is the nearest cube number to it for the remaining digits E.g -

$\sqrt[3]{1860867}$

Done with the last three digits and the last digit , & you get 3 as the last digit of $\sqrt[3]{1860867}$

Now find the nearest cube number of1860 & it is 12 (1728)

So therefore $\sqrt[3]{1860867}$ = 123

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So we just do the same ways... Thank you so much..

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Do I have to learn all cubes from 11 to 99 for this method? Isn't there a better method?

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waitwaitwaitwaitwait..whaaaaaaaaaaat? Where did that 3 even come from? The last digit of 1860867 is 7.....

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1), 4 (4³ = 64), 5 (5³ = 125), 6 (6³ = 216), 9 (9³ = 729) and 0 (0³ =0). But, here we see, it doesn't happen for 2 (2³ =8), neither 3 (3³ = 27), nor 7 (7³ = 343) and 8 (8³ = 512). I'll always have to check this before find cube roots by this method.Log in to reply

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Another Interesting fact:: (A) cube of 2= unit digit 8 .....cube of 8=unit digit 2 (B) cube of 3=unit digit 7...... cube of 7= unit digit 3

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1, 4, 5, 6, 9 have the unit place of their cubes as the number themselves. But cubes of 2,3 and 8,7 has there unit place as their compliment of 10.

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Thank you, a great method to solve the cube roots, so bad it doesn't work with every cubic root, it would save a lot of time in tests. Anyway, thanks!

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It works for groups of threes. How adorable.

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Write a comment or ask a question...if m=29 and e=13, then m=m+e e=m-e m=m-e then find the new value of m and e??

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But it is not useful for non perfect cubes

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I gave the first person who introduced this to me a very good comment. Features of natural numbers can occasionally been found. Important thing is never let this concept to mislead ourselves when the situation is not whole numbers. I recalled and remember ed again but not really memorized properly. Understand why could make me a better memory perhaps. Hope I can memorize from today onwards!

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Really cool way...I m looking forward to u to post some cool ways of finding the sum of series....

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cool

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@Kartik Kulkarni .... really a nice one ... but i hav a doubt ... take 1331 ..... u get 11 by the method stated above .... if u take 1441 ..... 11 isnt correct ..... in that case .... u cant find whether a no. is a cube no. or not using this method.... rite???

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Well actually,this method is only applicable for actual cube numbers

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@Kartik Kulkarni ... as soon as i saw ..... i found this interesting and also concluded this is applicable for perfect cubes ... but ur inference of 1441's cube root is around 11 is wrong ..... eg: take 1721 ..... if u infer by the same method as u did above ... it is around 11 ... but actually it can be estimated to 12 ..... (Note: cube root of 1721 = 11.98)

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Great buddy. Here is the actual method https://brilliant.org/discussions/thread/long-divison-method-of-cube-root/

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also 1441's cube root is somewhat 11 And many more numbers after the decimal points

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can someone prove it mathematically?

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a + 10 b + 100 c + 1000 d + 10000 e + 100000 f could roughly prove it I guess.

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https://brilliant.org/discussions/thread/long-divison-method-of-cube-root/

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maths is not about approximation and estimation!!!!

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Brilliant! Good to learn this from you. Thanks.

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Fantastic method Thanks

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Would largely help me for finding Karl Pearson's coefficient. Thanks.

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Nice note

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Awesome and unique way to do it!! Thanks!!

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Just noticed. It actually isn't applicable to numbers other than perfect cubes. For example, if you calculate the cube root of 1,216 using this method, you get 16; actual root is 10.67. They're almost 5.5 numbers apart. If you have any better ways, please post it.

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I had answered to a similar question , & this method is only applicable for numbers which have their cube roots with no numbers after the decimal point

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In that case we know between which two integers the actual cube root lays.

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Excellent method

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Thanks

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Write a comment or ask a question... Super

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Good solution

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ecellent method .its working

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Really good method... I like it!

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Very helpful. Thank you!

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Great! Interesting!

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Thank U Very Much.I like Ur Way To solve The Problem.

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excellent

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you mean x^3 of 226981 , 226971 , 226961 , 226981 , 226881 , all is 61 only by your way. which is incorrect

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I'm sorry I did not understand

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By this trick cube root for last 3 digit is depends on unit place digit only? if we consider these numbers which all have 1 as unit place digit , 226981 , 226971 , 226961 , 226221 , 226881 so by the rule cube root should be 61 for all these numbers. which is actually incorrect because numbers are different.

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you have to know that it it works only for a perfect cube

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nice

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I like this method .

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Real nice method. I liked it.

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i like that method

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Who discovered this method? It's really awesome

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I like it

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excellent method!!! upvoted young mind :)

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Only works for whole numbers. It's interesting however that you have found this method. How did you come across it?

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I HAVE SOME CONFUSION THAT WHEN HAM LOG SAME NO. KO LIKHEGE OR KAB NHI........AS 1ST SUM MEN.......226 KA 6 LIKHE AND 981 KA 1 SO ANS. IS 61 BUT 148877 MEN 148 KA 5 KYU LAST NO TO 8 HA SO COMPLEMENTRY IS 2 BUT HERE IS 5..

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I would prefer not to use Hindi cause it is confusing me that you have mixed up English & Hindi

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do you want to know the exact long division method of finding cube roots though it tedious... :)

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sure.

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https://brilliant.org/discussions/thread/long-divison-method-of-cube-root/

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good one

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how to work out cube root of 216216. The answer on face is 66 but that is not the cube root.

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you have to it by long division method

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216216 is not perfect cube ! This method is only for perfect cube

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It's really coolest method ever.but can any1 suggests me methods for square root of a decimal number.for eg:square root of 0.56

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Really very useful trick Thanks:)

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Cool.......

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thats just for a sure perfect cube

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Good Method ....!!! Amazing...!!

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Very nice & thanks.

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But it is not apllicable everywhere..

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Data handling

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Cub of 2, 3, 7, 8 we have its compliment of 10.

For 2: it is 10-2=8...........for 8, it is 10-8=2............................ 3, it it 10-3=7, ......for 7, it is 10-7=3

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What if its a 7digit number?

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Thank you it is so easy to find cube root of any number thank you very much

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How to find the cube root of 155.3

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what if we have 7 digited number could u explane me how to do it please

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I just explained it to Jonathan Christianto above

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kk:":":":":":":thanku

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then we have to go by long divison actual method

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whats's wrong with these four numbers(2,3,7 and 8)? i mean these are the number which you will never find at the end of any "squared number"( at ones place i mean). and here too the same four number have different digits at ones place. by the way nice trick. thanks!

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Very nice and interesting solution

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knew that already

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according to this cube root of 125486 should be 56 but actually it is not

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I just found out when this method works,

for eg 125486. last 3 digits = 6, first 3 digist =5,

here 125 is perfect cube , hence it doesnt work.

MY findings = This method only works when neither of the components( 1st 3 digits & last 3 digits) are perfect cube but the number that is comprised of the components is a perfect cube.

In ur case 125486 aint a perfect cube cum 125 which i call a component is.

Hows my Theorem? Thumbs up!!

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OK. what about 125000?

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125000, fr last 3 digits =0, fr first 3 digits =5

cube root of 125000 is 50.

(Notice that 000 is nothing but 0 and not 1000, 0^3 is 0)

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125486 is not a perfect cube and so this method is not applicable for that number

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3√79510

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I love this mathed

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