# Fake Proves

AN ANYONE TELL ME THE MISTAKE IN IT....

Note by Aßhĩмanyu Singh
5 years, 7 months ago

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You can't cancel $$(10-10)$$

- 5 years, 7 months ago

The problem is in the fourth step, where you have cancelled (10-10) with (10-10), because it would be the same as cancelling 0 with 0, so before performing the fourth step, try to prove 0/0 =1. Seems it is equal to both. But wait, try to do it with some variations equating it with 3,4,5 and it will satisfy all values. That why the solution is called indefinite because its solution set includes indefinitely many numbers. Can lead to a paradox!!!

- 5 years, 7 months ago

hey, if i say that prob. is in 1st step only like we know that 4/4=1 , 2/2 =1 , 3/3 =1, therefore 100-100/100-100 = 1 then

- 5 years, 7 months ago

Let me give you a reason for it, i have not seen it anywhere, just formulated it here only, so it can be wrong too.To start, I can write (100-100)/(100-100) as [100/(100-100)] - [100/(100-100)] which is equal to (100/0) - (100/0), it would be the same as infinity - infinity, and let me remind you that infinity is just a concept rather than a number so the solution set contains infinite numbers. You can ask if you have a doubt in this explanation.

- 5 years, 7 months ago

BUT Y IS 100-100/100-100 = 1 INCORRECT , IF WE DONT WRITE ANY FURTHER EXPLANATION

- 5 years, 7 months ago

100-100 can have infinite values, that is why mathematicians write it as not definite. If you know how to solve quadratic equations, u must know they have two roots, For example:- let us take a quadratic equation in which x=1 and x=2. but can i write 1=x=2? Obviously not! This is the case

- 5 years, 7 months ago

ohk

- 5 years, 7 months ago

thnxxx frnd

- 5 years, 7 months ago

ohk

- 5 years, 7 months ago

Aiya, the problem is the first step lah. You cannot divide anything by 0, otherwise you get a undefined result.

- 5 years, 7 months ago