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Finding the 'x'

How can we solve these type of problems:

e.g. \[2^{x}=x\]

or, \[2^{x}=x^{2}\]

To find the possible value(s) of x.

Note by Dinesh Nath Goswami
2 years, 1 month ago

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1 vote

  Easy Math Editor

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Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
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\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
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\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

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use log in both this is the simplest way 1st one answer is no solution 2nd one has 2 solution I.e., 2&4

Abhishek Sharma - 2 years, 1 month ago

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actually it has 3 solutions

Jun Arro Estrella - 2 years, 1 month ago

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thanks...

Dinesh Nath Goswami - 2 years, 1 month ago

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Try using graphs and apply calculus.

Deepak Kumar - 2 years, 1 month ago

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thanks. I'll try that way.

Dinesh Nath Goswami - 2 years, 1 month ago

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Use logarithm too. That will make the problem easier.

Sachin Vishwakarma - 2 years, 1 month ago

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@Sachin Vishwakarma thanks...

Dinesh Nath Goswami - 2 years, 1 month ago

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