Waste less time on Facebook — follow Brilliant.
×
No vote yet
3 votes

Comments

Sort by:

Top Newest

Everyone has assumed that a1 and area of other "similar looking" sectors are equal, so that 4a1 is their total area. Similar assumption have been made for a2 also. But one needs to prove these assumptions.

Shubham Srivastava - 4 years, 6 months ago

Log in to reply

Here is the another method. Though the answer is same but the reasoning involved in this method is such that one doesn't require the above stated two assumptions, so there is no need to prove the assumptions.\[ Area Of Sector SOQ = \frac {90}{360} \pi r^2\] \[Area Of Semicircle STO = \frac {1}{2} \pi (\frac {r}{2})^2 = Area Of Semicircle QTO\] \[Sector SOQ = a_1 + Semicircle STO + Semicircle QTO - a_2\] \[\frac {1}{4} \pi r^2 = a_1 - a_2 + 2 \times (\frac {1}{2} \pi \frac {r^2}{4})\] \[a_1 - a_2 = \frac {1}{4} \pi r^2 - \frac {1}{4} \pi r^2 = 0\]

Shubham Srivastava - 4 years, 6 months ago

Log in to reply

0

Dharmik Panchal - 4 years, 6 months ago

Log in to reply

the answer is 3π/16

Anshul Chauhan - 4 years, 6 months ago

Log in to reply

4a1 + 4π(1/4)^2 - 4a2 = π(1)^2

Anshul Chauhan - 4 years, 6 months ago

Log in to reply

\(4a_1+4π(1/2)^2 - 4a_2 = π(1)^2\), implies \(a_1 - a_2 = 0\)

Adam Silvernail - 4 years, 6 months ago

Log in to reply

Comment deleted Apr 01, 2013

Log in to reply

@Bhargav Das hey isn't 0 is the right answer? by using similarity??

Do-Hyung Kim - 4 years, 6 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...