# Graph Proof of Euler's Identity

As you can see, the lines intersect to zero at $≈ 3.14$, or, at exactly $π$, which is $≈ 3.141592653589793238462643383279502884197169399375105820974944592307816406286 208998628034825342117067982148086513282306647093844609550582231725359408128481$ if you could zoom infinitely close to the graph

Therefore, the identity:

$\boxed{e^{πi} + 1 = 0}$

Note by A Former Brilliant Member
6 months, 3 weeks ago

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Sort by:

- 6 months, 3 weeks ago

Wrote this when I felt bored, as I wanted to prove something using pictures

- 6 months, 3 weeks ago

A very simpler proof by Taylor series is given in the brilliant itself here. Best for all those who knows calculus!

- 6 months, 3 weeks ago

Good - I don't know calculus but I've read it.

- 6 months, 3 weeks ago

Look at my comment about $6$ hours, @Hamza Anushath, in the Out Of Hours Comment Room.

I'm ashamed of you...

- 6 months, 3 weeks ago

@Hamza Anushath, I need to talk to you, in the Out of Hours Comment Room, now...

- 6 months, 3 weeks ago