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Thanks a lot! (No, this is the only set I've made)

I'm happy that you liked the problems, but I haven't been active lately so I couldn't continue posting. I'll be back soon and I'll keep posting.

If you would like questions of some select topics please leave a comment below, I'd try posting problems on them. Do check my profile to find other problems of mine, stay tuned for more!

You have provided awesome questions for Mechanics. I will enjoy solving some Thermodynamics and Magnetism problems. It'll be awesome if you could provide links to such sets. Anyways, you should make some more sets.

@Sravanth Chebrolu Thanks,A very nice set.
I really enjoyed solving your questions,i solved all the questions,feeling awsome.
Looking for more sets by you.Keep posting.

The problem " Gravity Niagara Falls This Time " has the exact answer 526588.2353 kg(per minute). Because,
mgh = (5000)(746)(100/85)(60). As you've said g=10 & h=50, we get m= 526588.2353 kg(per minute). Your answer is 527000. Why? It is a Bit Far from the exact answer. If we post the answer to the nearest integer, the answer is very clearly 526588 kg(per minute). Kindly tell, where am I wrong? Shouldn't the answer be more exact? Kindly notice this. I hope you will also get the answer 526588 kg(per minute), NOT 527000 which is far away from the correct one.

No problem. No need to sorry ... That happens ....... After all, we all are human .... And, please never call me Sir ... I am just a student like you and learning new things regularly ..... By the way, your this set "GRAVITY" was really creative and praiseworthy... Please keep on posting problems like this in future ! Thanks a lot for your knowledge sharing .....

@Rubayet Tusher
–
Thank you, very much I respect your comment sincerely, thanks for liking my set and forgiving me.

The question in discussion was posted long before when I was very new to this website and committed such mistake, in future I hope I will not do such things, thank you!

The question named Gravity slope forces has incorrect answer.
Work done by force will be equal to change in potential energy. hence 1 + 2 will be 2mglsin30... please correct me if i am incorrect somewhere

The mistake you've done is, you've missed out the "Friction" Case into calculation. We know, "mu"=tan(theta).
So, "mu" becomes tan(30)=(1/sqrt3). Then the WORK for lifting up the block will be ((98+98)(3))=588 Joules Itself. Then, as we have lifted the block up a HEIGHT of (3/2), So, the increase in it's potential energy will be mg(3/2)=294 Joules. Then The sum becomes 588+294=882 Joules which is the correct answer.

but mu=tantheta is only valid when it is the limiting case of sliding. Please refer standard texts. Also there is not mention of friction in the question.

They are amazing...... I learnt a lot about gravity and the twists in the questions.
They are quite brain teasing also !! Well..... What else can I say.
The questions are as brilliant and amazing as the same way u are....

Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

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## Comments

Sort by:

TopNewestAwesome! Have you made similar sets for other topics as well ?

People like you make brilliant an awesome place to learn . I am enjoying this set a lot. Please keep posting such questions, they are interesting!

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Thanks a lot! (No, this is the only set I've made)

I'm happy that you liked the problems, but I haven't been active lately so I couldn't continue posting. I'll be back soon and I'll keep posting.

If you would like questions of some select topics please leave a comment below, I'd try posting problems on them. Do check my profile to find other problems of mine, stay tuned for more!

Log in to reply

You have provided awesome questions for Mechanics. I will enjoy solving some Thermodynamics and Magnetism problems. It'll be awesome if you could provide links to such sets. Anyways, you should make some more sets.

Have you solved some of my sets and questions?

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No, I'll try when I find time :)

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@Sravanth Chebrolu Thanks,A very nice set.

I really enjoyed solving your questions,i solved all the questions,feeling awsome. Looking for more sets by you.Keep

posting.Log in to reply

The problem " Gravity Niagara Falls This Time " has the exact answer 526588.2353 kg(per minute). Because, mgh = (5000)(746)(100/85)(60). As you've said g=10 & h=50, we get m= 526588.2353 kg(per minute). Your answer is 527000. Why? It is a Bit Far from the exact answer. If we post the answer to the nearest integer, the answer is very clearly 526588 kg(per minute). Kindly tell, where am I wrong? Shouldn't the answer be more exact? Kindly notice this. I hope you will also get the answer 526588 kg(per minute), NOT 527000 which is far away from the correct one.

Log in to reply

Thanks for writing in sir! I am extremely sorry for not mentioning to round off your answer, it is my mistake.

I'm sorry for my mistake, please reply and give your views

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No problem. No need to sorry ... That happens ....... After all, we all are human .... And, please never call me Sir ... I am just a student like you and learning new things regularly ..... By the way, your this set "GRAVITY" was really creative and praiseworthy... Please keep on posting problems like this in future ! Thanks a lot for your knowledge sharing .....

Log in to reply

The question in discussion was posted long before when I was very new to this website and committed such mistake, in future I hope I will not do such things, thank you!

Log in to reply

The question named Gravity slope forces has incorrect answer. Work done by force will be equal to change in potential energy. hence 1 + 2 will be 2mglsin30... please correct me if i am incorrect somewhere

Log in to reply

The mistake you've done is, you've missed out the "Friction" Case into calculation. We know, "mu"=tan(theta). So, "mu" becomes tan(30)=(1/sqrt3). Then the WORK for lifting up the block will be ((98+98)(3))=588 Joules Itself. Then, as we have lifted the block up a HEIGHT of (3/2), So, the increase in it's potential energy will be mg(3/2)=294 Joules. Then The sum becomes 588+294=882 Joules which is the correct answer.

Log in to reply

but mu=tantheta is only valid when it is the limiting case of sliding. Please refer standard texts. Also there is not mention of friction in the question.

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Please see my solution for the same.

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They are amazing...... I learnt a lot about gravity and the twists in the questions. They are quite brain teasing also !! Well..... What else can I say. The questions are as brilliant and amazing as the same way u are....

Log in to reply

well, thank you Skanda................ Any suggestions????????????

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