1.)If x^3-xyz=2 y^3-xyz=6 z^3-xyz=20 Find the maximun of x^3+y^3+z^3

2.)If x^2+y=12=y^2+x Find x^2+y^2

*3.) x=(1/sqrt2)+(1/sqrt3)+(1/sqrt4)+...+(1/sqrt1000) find the most Integer that small than or equal x.

1.)If x^3-xyz=2 y^3-xyz=6 z^3-xyz=20 Find the maximun of x^3+y^3+z^3

2.)If x^2+y=12=y^2+x Find x^2+y^2

*3.) x=(1/sqrt2)+(1/sqrt3)+(1/sqrt4)+...+(1/sqrt1000) find the most Integer that small than or equal x.

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewestareefil baeng – Ashwin Chawla · 3 years ago

Log in to reply

The second math...is it have a condition for x and y? If they are both interger, you can just put the table and take your answer there! – Kawaii Kuma · 3 years, 8 months ago

Log in to reply

You have : x^2 +y = 12 x+y^2 = 12

Minus those 2, you will have : (x-y)(x+y-1) = 0 x=y=3 will be the answer so I won't do anything with it here.

So x+y = 1. Add those 2 equation up there, you will have : (x+y)^2 -2xy + x + y = 24

Replace x+y. Find xy. Use xy and x+y to know x and y. I think you won't find it...I don't really know!

Thanks for reading this :) – Kawaii Kuma · 3 years, 8 months ago

Log in to reply

– Areefil Raksanit · 3 years, 8 months ago

how do you know that its are =3?Log in to reply

– Kawaii Kuma · 3 years, 8 months ago

Do some math. Try to replace and find out. This works everytime if the number you are finding is not big (like from 1->10). When you have the answer, it is easier for you to figure how to do the math :)Log in to reply