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# Help!

Hey guys just about a month and a half ago i participated in the national math olympiad in my country organised by a cambridge school in my country.I finished up second and among the problems i didnt solve was also this one.I'm posting it here to see if anyone can help.I would really appreciate it. So,here's the problem.In the figure above $$ABC$$ is an iscoceles triangle$$AB=AC$$.$$AD$$ is drawn such that $$AD=AB=AC$$.If it is known that $$CAE=28$$degrees.Find $$EBD$$.

Note by Lawrence Bush
3 years, 6 months ago

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Because of the given fact, we can draw a circle centred at A through B, C and D. Then using angle at the centre is twice that at the circumference, we can deduce that $$\angle EBD = 14°$$. Hope this helps!

- 3 years, 4 months ago