# Help!

Hey guys just about a month and a half ago i participated in the national math olympiad in my country organised by a cambridge school in my country.I finished up second and among the problems i didnt solve was also this one.I'm posting it here to see if anyone can help.I would really appreciate it. So,here's the problem.In the figure above $$ABC$$ is an iscoceles triangle$$AB=AC$$.$$AD$$ is drawn such that $$AD=AB=AC$$.If it is known that $$CAE=28$$degrees.Find $$EBD$$.

Note by Lawrence Bush
3 years, 11 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

Because of the given fact, we can draw a circle centred at A through B, C and D. Then using angle at the centre is twice that at the circumference, we can deduce that $$\angle EBD = 14°$$. Hope this helps!

- 3 years, 9 months ago