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# HELP Inequality problem (from Studying Math FB page)

Let $$a, b, c$$ be non-negative real numbers. Prove that

$\frac{ ab}{a+4b+4c} + \frac{bc}{b+4c+4a} + \frac{ ac}{c+4a+4b} \leq \frac{ a+b+c}{9}$

Hi! :) I saw this difficult inequality problem on the Studying Math FB Page but haven't been able to solve it for a very long time! (No copyright intended!) Any help would be appreciated. Thanks! :)

Note by Happy Melodies
4 years, 1 month ago

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I have some solutions :)

- 3 years, 9 months ago

Could you please give it out?I tried homogenizing, linearization.The only other ways are expanding and then using some inequality like Muirhead or Holder.

- 3 years, 9 months ago

Maybe since the inequality it homogeneous creating a condition like $$a+b+c$$ might help? My other thought is try using Jensen's inequality because it's normally really useful with cyclic inequalities like this, and the $$9$$ looks Jensen-esque. You could always just multiply everything up and AM-GM/ Murihead's?

- 3 years, 11 months ago

Sure! I will try it out :) Thanks!

- 3 years, 11 months ago