Help on Physics Problem

I have started studying Physics recently.

I need some help in this problem on \(1\)-Dimensional Motion.

Suppose that a passenger intent on lunch during his first ride in a hot-air balloon accidentally drops an apple over the side during the balloon’s liftoff. At the moment of the apple’s release, the balloon is accelerating upward with a magnitude of \(4.0\) m/s\(^2\) and has an upward velocity of magnitude \(2\) m/s. What are the (a) magnitude and (b) direction of the acceleration of
the apple just after it is released? (c) Just then, is the apple moving upward or downward, or is it stationary? (d) What is the magnitude of its velocity just then? (e) In the next few moments, does the speed of the apple increase, decrease, or remain constant?

My solution is:
(a) 9.8 m/s\(^2\).
(b) Downward.
(c) For a moment, it will move upward as the last velocity is \(2\) m/s.
(d) Immediately after it is released the velocity is \(2\) m/s.
(e) Speed will increase downward.

Am I right, please?

Note by Muhammad Rasel Parvej
3 months, 3 weeks ago

No vote yet
1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

Hi....U r wrong saying (e) speed \(\color{red}{INCREASES DOWNWARDS }\), speed refers to magnitude of velocity which in this case is decreasing initially, reaches zero and then increase . But u can say that velocity increases downwards always even if it goes up initially.

Hari Govind Sekhar - 3 months, 2 weeks ago

Log in to reply

Well, I have the same view as you have.

But, I took 'in the next few moments' phrase to mean 'eventually'.

Thanks!

Am I right in other points, from a to d, please?

Muhammad Rasel Parvej - 3 months, 2 weeks ago

Log in to reply

Yes u r.....also when we talk of speed we dont mention dierection(downwarads )

Hari Govind Sekhar - 3 months, 2 weeks ago

Log in to reply

@Hari Govind Sekhar Thank you very much!

Muhammad Rasel Parvej - 3 months, 2 weeks ago

Log in to reply

@Pranshu Gaba, please have a look.

Muhammad Rasel Parvej - 3 months, 3 weeks ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...