I have started studying Physics recently.

I need some help in this problem on \(1\)-Dimensional Motion.

Suppose that a passenger intent on lunch during his first ride in a hot-air balloon accidentally drops an apple over the side during the balloon’s liftoff. At the moment of the apple’s release, the balloon is accelerating upward with a magnitude of \(4.0\) m/s\(^2\) and has an upward velocity of magnitude \(2\) m/s. What are the (a) magnitude and (b) direction of the acceleration of

the apple just after it is released? (c) Just then, is the apple moving upward or downward, or is it stationary? (d) What is the magnitude of its velocity just then? (e) In the next few moments, does the speed of the apple increase, decrease, or remain constant?

My solution is:

(a) 9.8 m/s\(^2\).

(b) Downward.

(c) For a moment, it will move upward as the last velocity is \(2\) m/s.

(d) Immediately after it is released the velocity is \(2\) m/s.

(e) Speed will increase downward.

Am I right, please?

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## Comments

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TopNewestHi....U r wrong saying (e) speed \(\color{red}{INCREASES DOWNWARDS }\), speed refers to magnitude of velocity which in this case is decreasing initially, reaches zero and then increase . But u can say that velocity increases downwards always even if it goes up initially.

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Well, I have the same view as you have.

But, I took 'in the next few moments' phrase to mean 'eventually'.

Thanks!

Am I right in other points, from a to d, please?

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Yes u r.....also when we talk of speed we dont mention dierection(downwarads )

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