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# Help required!

A particle moves along $$x$$- axis in such a way that its coordinate $$(x)$$ varies with time $$(t)$$ according to the expression $$x$$ = $$2 - 5t + 6t^{2}$$ meters. What is the initial velocity of the particle?

A. $$-5 m/s$$

B. $$-3 m/s$$

C. $$6 m/s$$

D. $$3 m/s$$

Please help me to find the answer.

Note by Sahba Hasan
1 year, 3 months ago

## Comments

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Initial velocity = first derivative at (t=0) = d/dt(2-5t + 6t^2) at (t=0) = ... · 1 year, 3 months ago

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Can you please elaborate, i didn't understand you Sir @Pi Han Goh · 1 year, 3 months ago

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what is the derivative of x = 2-5t + 6t^2?

If you substitute t = 0 for the answer you found previously, what does the value you found mean? · 1 year, 3 months ago

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Comment deleted Oct 07, 2015

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It's 12t- 5, answer is -5 · 1 year, 3 months ago

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Comment deleted Oct 07, 2015

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d/dt(2) = 0 · 1 year, 3 months ago

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You got my mistake, i forgot to find derivative of the constant 2. · 1 year, 3 months ago

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