# Help required!

A particle moves along $$x$$- axis in such a way that its coordinate $$(x)$$ varies with time $$(t)$$ according to the expression $$x$$ = $$2 - 5t + 6t^{2}$$ meters. What is the initial velocity of the particle?

A. $$-5 m/s$$

B. $$-3 m/s$$

C. $$6 m/s$$

D. $$3 m/s$$

Note by Sahba Hasan
2 years, 11 months ago

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Initial velocity = first derivative at (t=0) = d/dt(2-5t + 6t^2) at (t=0) = ...

- 2 years, 11 months ago

Can you please elaborate, i didn't understand you Sir @Pi Han Goh

- 2 years, 11 months ago

what is the derivative of x = 2-5t + 6t^2?

If you substitute t = 0 for the answer you found previously, what does the value you found mean?

- 2 years, 11 months ago

Comment deleted Oct 07, 2015

It's 12t- 5, answer is -5

- 2 years, 11 months ago

Comment deleted Oct 07, 2015

d/dt(2) = 0

- 2 years, 11 months ago

You got my mistake, i forgot to find derivative of the constant 2.

- 2 years, 11 months ago