\[\frac{2016^x+\underbrace{2016^2+2016^2+\ldots+2016^2}_{p \text{ times}}}{2016^y}=2016\]

where \(p,x\) and \(y\) are both positive integers

What is the value of \(\dfrac{x^3-y^3+2016xy}{2016xy}\)?

\[\frac{2016^x+\underbrace{2016^2+2016^2+\ldots+2016^2}_{p \text{ times}}}{2016^y}=2016\]

where \(p,x\) and \(y\) are both positive integers

What is the value of \(\dfrac{x^3-y^3+2016xy}{2016xy}\)?

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewest\( \text{There are infinite many solutions to this problem}\) – Sambhrant Sachan · 4 months, 3 weeks ago

Log in to reply

– Novril Razenda · 4 months, 3 weeks ago

Hmm, I know that but I'm so confused how to get another solutions in this problem .Log in to reply