Space time Invariant

Standard Minkowski space time Invariant definition tells us \[d\phi^2 = c^2 dt^2 -\sum_{n} (dx^n)^2 \] \(d\phi=\textrm{Space time Invariant}\)

"n"refers to all possible spatial coordinates"n" \textrm{refers to all possible spatial coordinates} Prove that Space time Invariant remains constant in all frame of references\color{#20A900}\textrm{Prove that Space time Invariant remains constant in all frame of references} Let's take the simplified form(only taking the one spatial dimension) for a Frame of reference ϕ2=c2t2x2\phi^2 =c^2t^2 -x^2 (Here cc = speed of light and uu =relative velocity between two reference frames )

For Another frame of Reference Lorentz transform says t=β(tuxc2)t' = \beta({t-\frac{ux}{c^2}}) (where β=11u2c2\beta= \frac{1}{\sqrt{1-\frac{u^2}{c^2}}} )

And x=β(xut)x' =\beta( {x-ut}) Now inserting these on that equation ϕ2=c2t2x2    ϕ2=c2β2(tuxc2)β2(xut)2\phi'^2 =c^2 t'^2- x'^2 \implies \phi'^2 =c^2 \beta^2 (t-\frac{ux}{c^2})-\beta^2(x-ut)^2 =c211u2c2(t22uxtc2+u2x2c4)11u2c2(x22uxt+u2t2)= c^2 \frac{1}{1-\frac{u^2}{c^2}} (t^2 -2\frac{uxt}{c^2}+\frac{u^2x^2}{c^4})-\frac{1}{1-\frac{u^2}{c^2}}(x^2-2uxt+u^2t^2) After simplifying ϕ2=c2t2x2=ϕ2\phi'^2= c^2 t^2 -x^2 = \phi^2 Which means ϕ=ϕ\phi=\phi' or Space time Invariant as a constant.

But the in original equation It is stated as dϕ2+dx2+dy2+dz2+(icdt)2=0d\phi^2 +dx^2 +dy^2 +dz^2 +(icdt)^2 =0

So is it Reasonable to include all possible spatial dimensions in that Minkowski space time equation? (Shown in the first)

Note by Dwaipayan Shikari
6 months, 2 weeks ago

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Hi @Dwaipayan Shikari, I can't figure out what you mean by "is it reasonable to include all possible spatial dimensions in that Minkowski space time equation?" Can you say more specifically what your question is?

Tiffany Wang - 6 months, 1 week ago

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I have seen only dx,dy,dzdx,dy,dz spatial dimensions in minkowski space time equation along with time dimension. It is true for 4d space . My question is , "Is it possible to add more spatial dimensions like dx,dy,dzdx,dy,dz ?"

Dwaipayan Shikari - 6 months, 1 week ago

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