A gun fires bullets of each of ,mass 1gram with velocity of 10m/s by exerting a constant force of 5 g weight. then the number of bullets fired per second is- (g=10 m/s^2)

please me of this problem and let me know the answer in detail.

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestWe know that force = change in momentum/time. Now force is 50 N. Change in momentum is = Number of bullets

1gram(v-u)=10number of bullets. We assume bullet is first at rest and then it attains momentum. So 50 = 10*number of bullets/1 second. Thus we get 5 bullets per secondLog in to reply