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# IMO 2012

Let ABC be a triangle with $$∠BCA = 90^ \circ$$, and let D be the foot of the altitude from C. Let X be a point in the interior of the segment CD. Let K be the point on the segment AX such that $$BK = BC$$. Similarly, let L be the point on the segment BX such that $$AL=AC$$. Let M be the point of intersection of AL and BK. Show that $$MK = ML$$

Note by Paul Ryan Longhas
2 years, 8 months ago