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$\dfrac{\sqrt{\cos 2x}}{\cos x} = \dfrac{\cos 2x}{\cos x \sqrt{\cos 2x}}$

$\dfrac{2\cos^2 x -1}{\cos x \sqrt{2\cos^2 x -1}} = \dfrac{2\cos x }{\sqrt{2\cos^2 x -1}}-\dfrac{1}{\cos x \sqrt{2\cos^2 x -1}}$

For first term setting $\sin x = u$ will convert it into a standard integral. For the second term first set $\sin x = u$ then then set $\dfrac{1}{t}=u$. This will convert it into a standard integral.

@A Former Brilliant Member
–
Oh that's great , what is your ranking (in around 8000 students i guess) , just curious , actually here in mathura , i joined only a local coaching(they were frauds) which was disastrous , and thus i want to check my level of preparedness.(i am not much confident)

@A Former Brilliant Member
–
That's amazing , with ranks around those you can guarantee a top 1000 AIR in JEE for sure , i guess? Are you revising the course , i mean is your syllabus finished entirely?

@A Former Brilliant Member
–
It was nice talking to you , please do share your strategy when you are free , or owing to privacy we could chat at slack if you want.

@A Former Brilliant Member
–
Mayank , you must be revising as the final stage for JEE , Or do you have to complete some left course topics like me ? I would be very thankful to you if you share your stats. and strategy , so that i can analyze my self better.

Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

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## Comments

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TopNewest$\dfrac{\sqrt{\cos 2x}}{\cos x} = \dfrac{\cos 2x}{\cos x \sqrt{\cos 2x}}$

$\dfrac{2\cos^2 x -1}{\cos x \sqrt{2\cos^2 x -1}} = \dfrac{2\cos x }{\sqrt{2\cos^2 x -1}}-\dfrac{1}{\cos x \sqrt{2\cos^2 x -1}}$

For first term setting $\sin x = u$ will convert it into a standard integral. For the second term first set $\sin x = u$ then then set $\dfrac{1}{t}=u$. This will convert it into a standard integral.

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Hey nice approach , thank you bro, i wonder if you are this good from self - study or do you go to some good coaching? $\ddot\smile$

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Self study. Although I have taken DLP from Resonance.

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@Md Zuhair , @Mayank Singhal , guys any help?

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Let me try ... :)

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