Can somebody prove that the A.M of \(n^{th}\) powers is greater than the \(n^{th}\) power of A.M for \(n>1\) or, \[\dfrac{\sum_{x=1}^{n}a_x^n}{n}>[(\dfrac{\sum_{x=1}^{n}a_x}{n})^n]\]

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TopNewestCheck out Power Mean (QAGH) . – Calvin Lin Staff · 1 year, 8 months ago

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– Adarsh Kumar · 1 year, 8 months ago

Thank you sir!Log in to reply