# Interesting Sum

$\large { \left( \tan { x } \right) }^{ 2 }={ \left( \sin { x } \right) }^{ 2 }{ +\left( \sin { x } \right) }^{ 4 }+{ \left( \sin { x } \right) }^{ 6 }+{ \left( \sin { x } \right) }^{ 8 }+\cdots$

Prove the trigonometric identity above.

Note by Joel Yip
4 years, 9 months ago

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$\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{S=\dfrac{\sin^2 x}{1-\sin^2 x} = \dfrac{\sin^2x}{\cos^2 x} = \boxed{\tan^2x} }}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}$

- 4 years, 9 months ago

wow it looks like a pyramid. How long did you take to type and count so many boxes :)?

- 4 years, 9 months ago

- 4 years, 9 months ago

100% vella! Just like @Mehul Arora

- 4 years, 7 months ago

Haha, I actually copy pasted the latex from some other note :P

It is related to Andrew's recent problem :3

- 4 years, 7 months ago

The sum of an infinite GP can only be calculated when $-1. However $\sin^2x$ can be equal to 1. Can you justify?

- 4 years, 7 months ago

It should be specified that $|\sin x|<1$

- 4 years, 7 months ago

Well it is already in the range!

- 4 years, 7 months ago

Interesting!

- 4 years, 9 months ago

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