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# Last 3 digits

find last 3 digits of $2013^{2012^{2011^{\cdots^{3^{2^1}}}}}$

Note by Idham Muqoddas
4 years ago

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Also if you want to have more harder application of euler totient theorem then , do the full article . It is very nice article. · 4 years ago

do you know any other such articles especially for indian olympiad...? · 4 years ago

There are many many articles on AOPS also tell me more precisely , which topic? · 4 years ago

Depends whether you work from the top down or bottom up.

Top down: $$13^{12}$$ Bottom up: $3^{100}$ · 4 years ago