Check Letters Chatters.

Taking a general Case,

In a town with a population of \(n\), a person sends 2 letters to 2 random distinct people in the town, each of whom repeats the procedure. Thus, for each letter received, two letters are sent to 2 random distinct people (could even be to the person who sent the letter).

It is Assumed that all the letters reach their respective destination.

Just If the probability Of Letter to reach their respective Destination is \(\dfrac{1}{2}\).

Then What Is the probability that in the first \(m\) stages, the person who started the chain letter will not receive a letter .

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TopNewestPratik Shastri Pranjal Jain brian charlesworth Jon Haussmann Calvin Lin Azhaghu Roopesh M Ronak Agarwal megh choksi Abhishek Sinha Sandeep Bhardwaj Santanu Banerjee Sanjeet Raria Michael Mendrin

Any Helps On this One?? – Vraj Mehta · 1 year, 11 months ago

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@Pratik Shastri ,@Pranjal Jain ,@brian charlesworth sir,@Ronak Agarwal ,@megh choksi ,@Sandeep Bhardwaj sir,@Santanu Banerjee ,@Sanjeet Raria ,@Michael Mendrin sir,@Kishlaya Jaiswal ,@Kartik Sharma .

@Brock Brown ,Is a Python code possible (just curious :) ) ? – Azhaghu Roopesh M · 1 year, 11 months ago

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@Raghav Vaidyanathan – Vraj Mehta · 1 year, 10 months ago

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@Vraj Mehta Also look at the original problem and it's disputes. – Raghav Vaidyanathan · 1 year, 10 months ago

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– Raghav Vaidyanathan · 1 year, 10 months ago

Yes, I did see this. And i did think about it. But after a while it overwhelmed me. May not be possible to solve this by hand. Will try to do it again sometime.Log in to reply

– Vraj Mehta · 1 year, 10 months ago

I think this has some similarities with the Hydra questionLog in to reply

– Azhaghu Roopesh M · 1 year, 10 months ago

Isn't the solution not given in that book ?Log in to reply

@Pratik Shastri 's Book?? – Vraj Mehta · 1 year, 10 months ago

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– Azhaghu Roopesh M · 1 year, 10 months ago

Yeah .Log in to reply

And I thought Of this Extension While solving it..

Pratik Shastri And I discussed about it,but found dead Ends – Vraj Mehta · 1 year, 10 months ago

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– Azhaghu Roopesh M · 1 year, 10 months ago

Ok , I'll try it tomorrow .Log in to reply