# Maximum Area of Intersection

Squares ABCD and EFGH of side 12 are such that E is in AD, segments FG and GH intersect BC at X and Y, respectively, and 3GY=4GX. Let R be the region common to the interior of both squares. That is the minimum possible value of the area R?

Any ideas?

Note by Leandre Kiu
5 years ago

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do you know the answer?

- 5 years ago

nope :(

- 5 years ago