Squares ABCD and EFGH of side 12 are such that E is in AD, segments FG and GH intersect BC at X and Y, respectively, and 3GY=4GX. Let R be the region common to the interior of both squares. That is the minimum possible value of the area R?

Any ideas?

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TopNewestdo you know the answer? – Christian Baldo · 4 years, 1 month ago

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– Leandre Kiu · 4 years, 1 month ago

nope :(Log in to reply