ummm... I think that the answer is 0; It can be as small as you like
Consider connecting all 4 corners of the wall to a single point, forming a solid. Now take a cross section parallel to the wall, and place the mirror at the intersection of that cross section and the solid. Then technically, somebody standing at the reflection of the original point through the mirror could see the whole wall. Provided they are transparent.

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TopNewestummm... I think that the answer is 0; It can be as small as you like Consider connecting all 4 corners of the wall to a single point, forming a solid. Now take a cross section parallel to the wall, and place the mirror at the intersection of that cross section and the solid. Then technically, somebody standing at the reflection of the original point through the mirror could see the whole wall. Provided they are transparent.

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Rahul the proof can be found ind a ICSE 9 book in chapter light.

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The size of the wall = a Therefore the minimum size of mirror required to view the full wall = a/2 = n So, n/a = a/2a = 1/2.

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the value of n/a=1/3............ but how can we prove??????????

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