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If \(\log{x} = b - \log{n}\), find \(x\)

Note by A Brilliant Member 2 years ago

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\( \log{x} = b - \log{n} \implies x= 10^{b-\log{n}} \\ \boxed{ x = \dfrac{10^{b}}{n} } \)

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Logx=b-logn Logx+logn=b Log(xn) =b xn=10^b X=10^b/n

10^b/n

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Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

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`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

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TopNewest\( \log{x} = b - \log{n} \implies x= 10^{b-\log{n}} \\ \boxed{ x = \dfrac{10^{b}}{n} } \)

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Logx=b-logn Logx+logn=b Log(xn) =b xn=10^b X=10^b/n

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10^b/n

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