Let F=0.841818181818181..... When F is written as a fraction in lowest terms,the denominator is exceeds the numerator by: a-13 b-14 c-29 d-87

Note by Mehdi Balti
3 years, 2 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

let $$F=0.8418181818...$$

so $$100F=84.18181818...$$

$$\implies 100F-F=(84.18181818...)-(0.8418181818...) \implies 99F=83.34 \implies F=\frac{8334}{9900}=\frac{463}{550}$$

$$550-463=87$$ so the answer is $$d-87$$

- 3 years, 2 months ago

Thanks @Dedik KaitoKid Love you :)

- 3 years, 2 months ago

$$F = 0.84\dot{1}\dot{8} = 0.84 + \dfrac{18}{9900} = \dfrac{0.84\times 9900+18}{9900} = \dfrac{8316+18}{9900} = \dfrac{8334}{9900} = \dfrac{463}{550}$$

$$\Rightarrow 550 - 463 = \boxed{87}$$

- 3 years, 2 months ago