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NMTC-- Final Level

ABCD is a quadrilateral inscribed in circle with center O. Let BD bisect OC perpendicularly.P is a point on the diagonal AC such that PC=OC. BP cuts AD at E and the circle at F. Prove that PF is the geometric mean of EF and BF.

Note by Piyush Maheshwari
2 years, 11 months ago

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