For how many positive integral values of N is the expression N(N-101) the perfect square of a positive integer ?

I got 2601 as the only value. I want to know if there are other such values ? I know it's a silly question for Brilliant problem solvers. Please help.........

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TopNewestLet \(x^2=N\) and

\(y^2=N-101\) where \(x>0,y>0\)

Now we can write from our first statement that :

\(y^2=x^2-101\)

\(\Rightarrow x^2-y^2=101\)

\((x+y)(x-y)=101\)

Therefore it follows that \((x+y)\) and \((x-y)\) are factors of \(101\).

Now since \(101\) is a prime and \(x,y\) are positive integers then the only possible values that \((x+y)\) can take is \(101\).

Note that since \(x>y\) \(,\) \((x-y) \neq 101\).

So the only solution possible is when \(x=51\) which gives \(y=50\).

Therefore \(N=x^2=2601\) is the only solution. – Aditya Parson · 4 years, 2 months ago

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– Calvin Lin Staff · 4 years, 2 months ago

You need to substantiate your first line. Why must we have \(N=x^2\)? You are merely given that \(N\) is an integer, and not told that it is a square. For example, if we ignore the condition that \( N(N-101)\) must be positive, then \(N=101\) will be a solution, but that disagrees with your claim that \(N\) must be a perfect square.Log in to reply

– Aditya Parson · 4 years, 2 months ago

If \(N=101\) is a solution then \(y=0\) but I already stated that \(y>0\). So N=101 cannot be a solution.Log in to reply

it came in isi right – Superman Son · 4 years, 2 months ago

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– Raja Metronetizen · 4 years, 2 months ago

yea,you too gave isi,how many could you answer in part i & II...?Log in to reply

– Nishant Sharma · 4 years, 2 months ago

Yeah it was an ISI problem. Well I attempted 29/30 in part I and solved 4 in part II. How about you both ?Log in to reply

– Superman Son · 4 years, 2 months ago

i am 13 so i cannot participate but i saw the question and tried to solve it . i got about 28 in part 1 and 7 in part 2Log in to reply

age) ? Anyway, where from did you get the questions ? – Nishant Sharma · 4 years, 2 months agoLog in to reply

– Superman Son · 4 years, 2 months ago

y kiddin and q from http://cheentaganitkendra.blogspot.in/2013/05/isi-2013-bmath-bstat-subjective-paper.htmlLog in to reply

You are missing another obvious (positive integral) solution. (This statement is false. See edit below.)

Hint: Greatest Common Divisor.

Edit: I missed out that \(N (N-101)\) has to be the square of a

positiveinteger. I was thinking that \(N=101\) works. – Calvin Lin Staff · 4 years, 2 months agoLog in to reply

– Nishant Sharma · 4 years, 2 months ago

Seriously could not follow you. Please extrapolate a bit.Log in to reply

– Shourya Pandey · 4 years, 2 months ago

I don't think that any other solution exists, Calvin Sir. Both \(N\) and \(N(N-101)\) are to be positive.Log in to reply

– Calvin Lin Staff · 4 years, 2 months ago

I misread, didn't see "positive" in the latter instance. Thanks for correcting.Log in to reply

– Nishant Sharma · 4 years, 2 months ago

Me too. That was why I posted this since I had done few problems only. BTW did you also write ISI 2013 ?Log in to reply

– Superman Son · 4 years, 2 months ago

yesLog in to reply