Two identical blocks A and B each of mass M are placed on a long inclined plane (angle of inclination = θ ) with A higher up than B. The coefficients of friction between the plane and the blocks A and B are respectively µ A and µ B with tan θ > µ B > µ A. The two blocks are initially held fixed at a distance d apart. At t = 0 the two blocks are released from rest.

Find the time in which the two blocks collide?

My answer ; - $\large{t_{Collision} = \sqrt{\dfrac{2d \tan \theta ( \sin \theta - \mu_A \cos\theta)}{g (\sin \theta - \mu_B \cos\theta)}}}$

What about you?Is my answer correct?

**I am not sure with my answer, please all of us, lets discuss!**

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## Comments

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TopNewestThe two blocks will meet up after a time $t$ such that

$d + \dfrac{g}{2}(\sin(\theta) - \mu_{B}\cos(\theta)) = \dfrac{g}{2}(\sin(\theta) - \mu_{A}\cos(\theta))$,

which when solved for $t$ gives us $t_{c} = \sqrt{\dfrac{2d}{g\cos(\theta)(\mu_{B} - \mu_{A})}}$.

Suppose $\mu_{A} = \mu_{B}$. Then you wouldn't expect the two blocks to ever meet, but your formula would have them meeting after $\sqrt{\dfrac{2d\tan(\theta)}{g}}$ seconds, while mine would have $t_{C} \to \infty$ as expected.

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This seems to be a generalization of that "underkill" problem that was posted recently.

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Exactly. I found it a bit odd at first that $\cos(\theta)$ was in the denominator, since this would result in a finite $t_{c}$ for $\theta = 0$, which doesn't make sense, (although an infinite $t_{c}$ for $\theta = \pi/2$ does make sense as the two blocks would both be in free-fall so A would never catch up). But then I remembered that we require that

$\tan(\theta) \gt \mu_{B} \Longrightarrow \theta \gt \arccos\left(\dfrac{1}{\sqrt{1 + \mu_{B}^{2}}}\right)$.

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Which underkill problem? Can you please provide the link sir?

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One can generalise further : If the time at which they first meet is $t_{1}$, the subsequent times of meeting again (after collision) turns out to be odd multiples of $t_{1}$

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my friends are expecting around 310-315

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I'll take your word for it(if i write advanced)

thank you!

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@Rohith M.Athreya are you giving either of ISI or CMI ?

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II no

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Thanks sir!

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Even I got the same answer as you sir. :)

@Md Zuhair From where did you get this problem?

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i did a very fine mistake! Its correct now!

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@Md Zuhair Yup, my answer matches with the one given by Brian Charlesworth and yes, its correct :-) ! Sorry yours was wrong :-( .

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Ya I got it now

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Let me tag some of you,

@Aniket Sanghi , @Rohith M.Athreya , @Ayon Ghosh , @Steven Chase , @Brian Charlesworth!

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http://olympiads.hbcse.tifr.res.in/olympiads/wp-content/uploads/2017/01/INPhO2017-Solution-20170131.pdf

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