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Please find the minimum value:

a,b are natural no's .
2013+\(a^2\)=\(b^2\).
Find the minimum possible value of ab?

Note by Kandarp Singh
2 years, 12 months ago

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658? Krishna Sharma · 2 years, 12 months ago

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@Krishna Sharma yeah but how Kandarp Singh · 2 years, 10 months ago

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hi. See that \(a^2-b^2=(a+b)(a-b)=2013\). And since \(a\) and \(b\) are integers, so have to be \(a+b\) and \(a-b\). Then you can work out the factors of \(2013\) to get \(a\) and \(b\), and then it's easy to tell which one will give the minimum product. Satvik Golechha · 2 years, 12 months ago

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@Satvik Golechha In general I simply find max{|a-b|} for ab to be minimum Krishna Sharma · 2 years, 12 months ago

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