Given that ABCD is a parallelogram and A(1,1,0) B(-1,-1,-1) C(2,2,0) then what are the co-ordinates of D ? Also find the area of parallelogram ABCD ?

A triangle has 2 sides of length 5 and 6. The triangle's area is 12 .What is the angle between these two sides ?

Given the points A=(1,0,1) and B(1,1,1) and C(1,6,a) determine : (a) For what values of z are the points collinear ? (b) Determine if value exists for a so that A, B, c are three vertices of a parallelogram of area 3. If the value exists determine the co-ordinates of C ?

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## Comments

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TopNewest1. Find the mid point of AC (diagnol) and then apply section formula (here mid point formula) on BD as it is also the mid point of BD. Because in ||gm Diagnols bisect each other.

2.Area of triangle when two sides and angle contained between the sides are given is \(\frac{1}{2}ABsin\theta\) A and B are the lengths of sides.

\(\frac{1}{2}5.6sin\theta\)=12.

\(sin\theta\)=4/5

\(\theta\)=53 degrees

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3 one is lengthy thats why i m not writin that BUT 3 part is deeply same as 1 st part.

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Thanks !!

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