The new year has come upon us, and with it a new number to work with. Because of this, I want to compile a list of properties and facts about the number 2018 for use in competitions and problem writing. This can include relationships with other numbers, ways to formulate it as an expression, and expressions involving it; however, any fact about 2018 that could be used in a competition setting can belong here.

I'll start this list off with some basic facts:

- 2018 is even.
- The prime factorization of 2018 is \(2 \times 1009.\)
- 2018 has four digits.
- The sum of the digits of 2018 is 11.
*etc. etc. etc.*

Feel free to contribute anything about the number 2018 in the comments!

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## Comments

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TopNewest2018 is the sum of 4 distinct nonzero fourth powers:

2^4 + 3^4 + 5^4 + 6^4

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cvbnm,.

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vbnm

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2018 can be written as a sum of 4 consecutive positive integers, but not as a sum of any other number of consecutive positive integers. This sum is \(503+504+505+506 = 2018\).

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2018 is the number of ways we can partition 60 into prime parts

here are the first 10 partitions of 60 into prime parts:

`{53,7},{53,5,2},{53,3,2,2},{47,13},{47,11,2},{47,7,3,3},{47,7,2,2,2},{47,5,5,3},{47,5,3,3,2},{47,5,2,2,2,2}...`

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good solution

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, ,,n ,

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2018 has 4 positive divisors.

Sum of the 4 positive divisor of 2018 is 3030.

2018 is one larger than a prime number.

2018 can be expressed as the sum of two perfect squares. \(13^2+43^2 = 2018\)

Etc...

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\(\text{● 2018 in binary=}\)\(\text{11111100010 base of two}\)

\(\text{● Divisors = 1, 2, 1009, 2018}\)

\(\text{● Count from 1 upto 2018 take 33 minutes.}\)

\(\text{• 2018 is a deficient number, because the sum of its proper divisors (1012) is less than itself. Its deficiency is 1006.}\)

\(\text{• 2018 is a UnLucky number.}\)

\(\text{• 2018 is a UnHappy number. }\)

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There are two ways to formulate it as the sum of the difference of two sets of consecutive cubes.

(9^3-8^3) + (25^3 - 24^3)

8&9 are consecutive, 24&25 are consecutive.

and

(15^3-14^3) + (22^3 - 21^3)

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\(2018\) can be written as a sum 2 perfect squares of which the first digit is perfect square (\(1^2, 2^2\)) repectively and the last digit is both \(3\) : \(2018=13^2+43^2.\)

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2018 is a Squarefree composite number such that the sum of its divisors is also Squarefree

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Indeed. I wrote a little problem about this property: it is quite "rare" among all year numbers.

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Can 2018 be expressed as the difference of two powers ? 2018 = m^n - p^q ? where m, n, p and q are all prime ?

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I had got this straight away, and posted a true way, but I suddenly realised that it had a very strong correlation to one of the problems in the Popular section, and have removed it.

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2018 is a semiprime that is a prime+1

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2018 in different number bases:

base 2: 1111110010

base 3: 2202202

base 4: 133202

base 5: 31033

base 6: 13202

base 7: 5612

base 8: 3742

base 9: 2682

base 10: 2018

base 11: 1575

base 12: 1202

base 13: BC3

base 14: A42

base 15: 8E8

base 16: 7E2

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