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# PROVE 1 + 1 = 3 AND IF YOU FIND IT DIFFICULT, SEE MY SOLUTION ATTACHED

$$-2 \times -1$$ = $$2$$

taking log to the base ten on both sides we get

$$log -2 + log -1$$ = $$log 2$$

$$-log \frac{1}{2} + log -1$$ = $$log 2$$ SINCE $$log -a$$ = $$- log \frac{1}{a}$$

$$log -1$$ = $$log 2 + log \frac{1}{2}$$

this can be written as

$$log -1$$ = $$log \frac{2}{2}$$

$$log -1$$ = $$log 1$$

this implies $$log -1^{3}$$ = $$log -1^{2}$$ since $$-1^{3}$$ = $$-1$$ AND $$-1^{2}$$ = $$1$$

$$3$$ $$log -1$$ = $$2$$ $$log -1$$

dividing by log -1 to the base ten on both sides,we get

$$3$$ = $$2$$

$$3$$ = $$1$$ + $$1$$

sorry this is a wrong proof

Note by Revankumar Gnanavel
4 years, 1 month ago

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Note that the logarithm formula is $$-\log \frac {1}{a} = \log a$$, not "SINCE $$\log -a = - \log \frac {1}{a}$$" as you claimed. Staff · 4 years, 1 month ago

thanks for correcting my mistake · 4 years, 1 month ago

i appreicate ur attempt for doing this,i request u think more like this....... (eppadi da room pottu yosipeengaloooo...)-just for fun · 4 years, 1 month ago