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# Seems simple?

Prove that for every natural number $$n$$, there exists a prime number $$p$$ such that $$p < n < 2p$$.

Note by Achal Jain
10 months, 2 weeks ago

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It is just Bertrand's postulate, applied as, $\frac{n}{2} < p < {n}$ · 10 months, 1 week ago