# shortest perimeter

Between the various triangles on same base and between the same parallel lines which one would have the shortest perimeter... isosceles, equilateral or other? how can we prove it?

Note by Rahul Vernwal
5 years, 8 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

## Comments

Sort by:

Top Newest

Sreejato, I would disagree with you. The main issue lies in understanding what Rahul meant in his problem, which could be stated clearer.

My interpretation of the problem is as follows: We are given 2 points $$A$$ and $$B$$ and a line $$\ell$$ which is parallel to $$AB$$. Consider all triangles $$ABC$$ with $$C$$ on $$\ell$$. Which triangle has minimal perimeter?

Staff - 5 years, 8 months ago

Log in to reply

Sir then is the length $$AB$$ and the perpendicular distance from $$\ell$$ constant?

- 5 years, 8 months ago

Log in to reply

Comment deleted Apr 04, 2013

Log in to reply

I don't really think this is correct. I believe you meant $$A=(0,0), B=(c,0), C=(x,h).$$ Perimeter$$=c+\sqrt{x^2+h^2}+\sqrt{(c-x)^2+h^2}$$. Ignore the $$c$$ since it is a constant and by AM-GM the minimum is obtained when $$\sqrt{x^2+h^2}=\sqrt{(c-x)^2+h^2} \Rightarrow x=c-x \Rightarrow x=c/2$$, which is an isosceles triangle. Anyway I prefer Gabriel's solution.

- 5 years, 8 months ago

Log in to reply

Yes. There is a much more direct approach to this problem, where the triangle inequality hides all the algebraic expressions that you use.

Hint: Reflect $$B$$ across line $$\ell$$.

Staff - 5 years, 8 months ago

Log in to reply

Using Calvin's intepretation, we have: Villages A, and B lie on a straight line. There is a river parallel to the line containing A and B. What is the fastest way to run from A to the river and back to B? The answer is simple: reflect B across the river to obtain B'. The distance from the river to B and distance to B', for any point on the river, is the same. So the best point (C) on the river is the intersection of AB' and the river, which makes triangle ABC iscoceles.

- 5 years, 8 months ago

Log in to reply

Between the various triangles on same base and between the same parallel lines which one would have the shortest perimeter... isosceles or other? how to prove it? think of the case when base length is less than the perpendicular distance between parallel lines?

- 5 years, 8 months ago

Log in to reply

Comment deleted Apr 04, 2013

Log in to reply

and what if the triangle cannot be equilateral? i mean if it cannot be formed that way

- 5 years, 8 months ago

Log in to reply

Please clarify how it can be formed.

- 5 years, 8 months ago

Log in to reply

when perpendicular distance between two parallel lines is greater then the height of equilateral triangle formed by using base length as length of sides.......

- 5 years, 8 months ago

Log in to reply

According to your specified constraints, an isosceles triangle is the best choice for minimizing the perimeter.

- 5 years, 8 months ago

Log in to reply

what does it mean?? type the full question

- 5 years, 8 months ago

Log in to reply

@ rahul

- 5 years, 8 months ago

Log in to reply

Please pardon me if I don't understand this properly but the perpendicular distance between two parallel lines when perpendicular distance between the two parallel lines is the height of equilateral triangle formed by using base length as length of sides.

- 5 years, 8 months ago

Log in to reply

equilateral<isoceles<abstract<right

- 5 years, 8 months ago

Log in to reply

yep

- 5 years, 8 months ago

Log in to reply

I'm going to manually edit the votes such that your post doesn't appear at the top.

Staff - 5 years, 8 months ago

Log in to reply

Fantastic solution!!. I also got the same answer but after using triogonometry, but you got it so effortlessly

- 5 years, 8 months ago

Log in to reply

right sreejato

- 5 years, 8 months ago

Log in to reply

it depends on lengths of rest two sides

- 5 years, 8 months ago

Log in to reply

Let the length of the base be taken as x. If the perpendicular distance is x√3 / 2 , then, the perimeter of equilateral triangle is 3x. The perimeter of right angled triangle is 3.025x . In this case Equilateral triangle and isosceles triangle is the same. So between 3x and 3.025x, 3x is smaller and equilateral triangle has shorter perimeter.

- 5 years, 8 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...