# solve this....

fathers age is 3 times the sum of ages of his 2 children .after 5 yrs his age will be twice the sum of ages of the two children . find the present age of father

Note by Pooja Arora
5 years ago

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Let the children's ages be $$x$$ and $$y$$ and the father's age $$z$$. So $$z=3(x+y)$$ and $$z+5=2(x+y+10)$$. Then we get $$z=2x+2y+15$$.Then we can substitute $$z=3(x+y)$$ which is $$z=3x+3y$$.So $$x+y=15$$,and $$z=45$$

- 5 years ago

Let $$c$$ be the sum of the 2 children's age and $$f$$ be the father's age

$$f=3c$$ ...(1)

$$5+f=2(c+10)$$ ...(2)

Simplifying (2): $$5+f=2c+20\Rightarrow f=2c+15$$

Combining (1) and (2): $$3c=2c+15$$. Therefore, we could get $$c=15$$

From (1): $$f=3c$$, we could get the father's age: $$f=3(15)\Rightarrow f=45$$

Therefore, the father's present age is 45 years old.

- 5 years ago