@Agr Amul
–
Yes. "The Projection of P onto AB is X" means "Drop a perpendicular from P to AB, intersecting AB at X".

Write out the equations of Pythagorean theorem. For example, \( XB^2 + BY^2 = OB^2 \). You should have 4 equations. Does that help you solve for the sides? Why, or why not?

Note: I am not claiming that there is a unique set of solutions. I'm merely guiding you down what is the next sensible / logical step to take. It is not guaranteed that this must lead to a solution.

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TopNewestHint: Read this wiki.

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How is this going to help? We can just get the value of x, nothing else.

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Great, that's a start. What can we do next?

If X, Y are the projections of O onto AB, BC, can we find AX, XB, BY, YC?

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Write out the equations of Pythagorean theorem. For example, \( XB^2 + BY^2 = OB^2 \). You should have 4 equations. Does that help you solve for the sides? Why, or why not?

Note: I am not claiming that there is a unique set of solutions. I'm merely guiding you down what is the next sensible / logical step to take. It is not guaranteed that this must lead to a solution.

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