hello , I really urgently need your help in this problem The product of 2 natural nos. is 15120 and their HCF is 6.Find how many such pairs exist.

Pls help me to find the solution to this problem

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TopNewestHint:Let \(A\) and \(B\) be the 2 integers. Show that \(\dfrac A6\) and \( \dfrac B6\) are coprime.Hint 2:Factorize \( \dfrac{15120}{6\times6} \) into product of 2 coprime posiitve integers.Log in to reply

I have factorized 420 by 7 and 5 and then??

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We know that \(A/6\) and \(B/6\) are coprime positive integers, and that \( A/6 \times B/6 = 420 \).

So we want to find 2 coprime positive integers that give a product of 420.

For example \( 1\times 420 \), \(4\times 105\), \(3\times35\), \(15 \times 7\).

Is there any other way?

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Are there any other larger integer that must divide both \(A\) and \(B\)?

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In other words, the largest integer that divides both \(A\) and \(B\) is....?

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420,4105,335,157 are the probable pairs.right??Log in to reply

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